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Enter text here.An acid solution is 0.120 M in HCL and .210 M in H2SO4, what volume of a .150 M KOH solution would have to be added to 500.0 mL of the acidic solution to neutralize completely all of the acid?
any freakin cluee how to do this!??!?!?:confused ::confused : ive been working for like 2hours on this. its due online at 12pm so any quick help would be very appreciated! ill let u have a import tuner magazine or something lol
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Last edited by Evan_2k; 09-29-2009 at 02:34 AM.
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0.5000 litres @ 0.120mol/litre = 0.0600 moles of HCl, which releases 0.0600 moles of H+ ion
0.5000 litres of 0.210 mol/litre = 0.105 moles of H2SO4, which releases 0.210 moles of H+ ion
0.210 & 0.060 = a total of 0.270 moles of H+ ion
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0.270 moles of H+ ion needs 0.270 moles of OH- ion
0.270 moles of OH- ion @ 0.150 mol/litre = 1.80 litres of KOH
your answer: 1.80 litres of 0.150 M KOH
you are a god... the H+ releasing from h2so4 was tricky!!! theres 2 god damn hydrogens!! i kept getting it wrong and it wouldnt let me submit,now I know why..... You can do this problem and not wire my foglight?? lol im jk, thank you so much peter i owe u one!
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Beans and rice are ment to be eaten, not driven.
Went to JH for the Summer program for Civil Engineering program now I'm at Cal State Fullerton and Santa Ana College, now I putting transfer paper to Alaska Pacific University or CU Boulder or Oregon State or USC to finish up my study and research in Environmental Geology/ Engineering....
Like what's the indefinite integral of e multiplied by x?
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