I'm no math wiz. I have a question or two for those of you much smarter than I. I will try to be as clear as possible. Here is my dillema!

Car A:
Weighs 2550lbs
Makes 114lb-ft of torque@6500rpm

Car B:
Weighs 2330lbs
Makes 145lb-ft of torque@6500rpm

Both cars are exactly the same otherwise.
Car B has 31 more lbs of torque (27% more) being applied to move 220lbs less weight. Is this extra amount of force significant enough to cause any problems on drivetrain components (AKA CVT) despite having to move 220lbs less weight? Is it about the same amount of wear-n-tear? Less? Am I asking the right question?

 

Damn..no answer!

Ok...simplest question is that I'm wondering if the CVT can handle an additional 29-30lb-ft of torque.




Personal notes {Please disregard}:
2015 Honda Fit
130hp @ 6600rpm
114tq @ 4600rpm

50hp shot of nitrous
180hp @ 6600rpm
143tq @ 6600rpm
+29tq **Will be less as 50hp shot is max. Usually comes out less**

2015 Honda Civic CVT
143hp@6500rpm
129tq@4300rpm
CVT handles +15tq more than Fit (Pretty much same CVT)

 

I think I found the answer to what I'm looking for in the new 2016 Honda Jade RS.

150lb-ft of torque. Close thread and carry-on...

Honda Jade RS launched in Japan with VTEC turbo engine

 

I'll take one of those Jade RS turbo engines please!

 

If you can find out what's the peak power the cvt can handle, then it should be able to handle at least 29 wtq. 29 wtq isn't like adding another 100wtq so i think you should be fine.